CS101 Assignment No. 2 Solution
Wednesday, April 27, 2011 Posted In CS and IT Edit ThisAssignment No. 02
Semester Spring 2010
Human-Computer Interaction-CS201
Total Marks: 15
Due Date: 27/04/2011
Objective:
To learn Boolean Logical operations and the basics of Word Processor and Spread Sheet
Instructions:
Please read the following instructions carefully before solving & submitting assignment:
Assignment should be in your own wordings not copied from net, handouts or books.
It should be clear that your assignment will not get any credit (zero marks) if:
- The assignment is submitted after due date.
- The submitted assignment does not open or file is corrupt.
- The assignment is copied from other student or copied from handouts or any internet source.
- Student ID is not mentioned in the assignment File or name of file is other than student ID.
- The assignment is not according to the given format
For any query about the assignment, contact at cs101@vu.edu.pk
Question No.1 (Marks = 10)
a) How many combinations of bits are exist when we make a truth table of 9 inputs? (2 Marks)
b) Prepare a truth table for the following I = (w + x) Å (y . z) where w, x, y and z are four binary inputs in the truth table. (8 Marks)
Note :(Å symbol represent XOR gate)
Question No.2 Write any three features and two limitations of each one in the given format (Marks = 5)
Features: (3 Marks)
Sr.No. | Word Processor | Spread Sheet |
1. | ||
2. | ||
3. |
Limitations: (2 Marks)
Sr.No. | Word Processor | Spread Sheet |
1. | ||
2. |
Note:
- Assignment should be in your own wordings not copied from net, handouts or books.
- Your answer should be “to the point”
Solution:
Answers
Question No.1 (Marks = 10)
a) How many combinations of bits are exist when we make a truth table of 9 inputs?
2n are the total combinations of bits in Truth table, where n is number of variables, so
29=512
512 bits will there
b) Prepare a truth table for the following I = (w + x) Å (y . z) where w, x, y and z are four binary inputs in the truth table.
Note :(Å symbol represent XOR gate)
Solution:
Remember in XOR, output will high only if only all inputs are mismatch to each others.
Inputs | Output | |||||
W | X | Y | Z | w+x | y.z | (w + x) Å (y . z) |
0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 1 | 0 | 0 | 0 |
0 | 0 | 1 | 0 | 0 | 0 | 0 |
0 | 0 | 1 | 1 | 0 | 1 | 1 |
0 | 1 | 0 | 0 | 1 | 0 | 1 |
0 | 1 | 0 | 1 | 1 | 0 | 1 |
0 | 1 | 1 | 0 | 1 | 0 | 1 |
0 | 1 | 1 | 1 | 1 | 1 | 0 |
1 | 0 | 0 | 0 | 1 | 0 | 1 |
1 | 0 | 0 | 1 | 1 | 0 | 1 |
1 | 0 | 1 | 0 | 1 | 0 | 1 |
1 | 0 | 1 | 1 | 1 | 1 | 0 |
1 | 1 | 0 | 0 | 0 | 0 | 0 |
1 | 1 | 0 | 1 | 1 | 0 | 1 |
1 | 1 | 1 | 0 | 1 | 0 | 1 |
1 | 1 | 1 | 1 | 1 | 1 | 0 |
Question No.2 Write any three features and two limitations of each one in the given format
Features: (3 Marks)
Sr.No. Word Processor Spread Sheet
1. Good Formatting Hand with Good Mathematical Hand
Integrate technology
2. Real word 2d drawing Good Drawing, Flow chart
Features of Spell and Grammatical error and charts.
checking
3. Direct mail attachment and Data recovery Options Data recovery, AutoSave and
And much more much more
Limitations:
Sr.No. Word Processor Spread Sheet
1. Calculation of Functions and relationship Limited Format styles w.r.t
MS word
Up gradation is very costly.
2 3D drawing not sported. Animations and special
Effects not present
There May many more limitations and features search them.
::::::::::::::::::::::::::::::
Definition for xor:
The logical operation exclusive disjunction, also called exclusive or (symbolized XOR, EOR, or ⊕), is a type of logical disjunction on two operands that results in a value of true if exactly one of the operands has a value of true. A simple way to state this is "one or the other but not both.".
The logical operation exclusive disjunction, also called exclusive or (symbolized XOR, EOR, or ⊕), is a type of logical disjunction on two operands that results in a value of true if exactly one of the operands has a value of true. A simple way to state this is "one or the other but not both.".
::::::::::::::::::::::::::::
Question No.1 (Marks = 10)
a) How many combinations of bits are exist when we make a truth table of 9 inputs? (2 Marks)
Answer :
29=512
512 bits
b) Prepare a truth table for the following I = (w + x) (y . z) where w, x, y and z are four binary inputs in the
truth table. (8 Marks)
Note :symbol represent XOR gate)
| W | X | Y | Z | W + X | Y.z |  |
| 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| 0 | 0 | 0 | 1 | 0 | 0 | 0 |
| 0 | 0 | 1 | 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 1 | 0 | 1 | 1 |
| 0 | 1 | 0 | 0 | 1 | 0 | 1 |
| 0 | 1 | 0 | 1 | 1 | 0 | 1 |
| 0 | 1 | 1 | 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 | 1 | 1 | 0 |
| 1 | 0 | 0 | 0 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 | 1 | 0 | 1 |
| 1 | 0 | 1 | 0 | 1 | 0 | 1 |
| 1 | 0 | 1 | 1 | 1 | 1 | 0 |
| 1 | 1 | 0 | 0 | 1 | 0 | 1 |
| 1 | 1 | 0 | 1 | 1 | 0 | 1 |
| 1 | 1 | 1 | 0 | 1 | 0 | 1 |
| 1 | 1 | 1 | 1 | 1 | 1 | 0 |
