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STA301 Assignment No. 2 solution

Wednesday, May 04, 2011 Posted In Edit This
Assignment 2 (Lessons 12-18)

Question 1:                                                                        Marks: 2+2+4+2=10
  1. By using five number summary, suggest the skewness of the data from the following information:
  1. What is the usefulness of Pearson’s coefficient of skewness?
  2. For a certain data,
Find moment ratios  and. Interpret your results also.
d.      Explain equally likely events with the help of an example.

Question 2:                                                                          Marks: 4+4+2=10 
a. For a particular data of 5 pair of values:
      The fitted regression line is:
Y= -1.5 + 0.5 x
Find the standard error of estimate (Sy.x); what doest it indicates?
  1. Five yellow balls and four green balls, which are indistinguishable apart from color, are placed in a bag if six balls are taken from the bag; Find the probability of being three yellow and three green.
  2.  If the equations of the least square regression lines are:
        Y= -1 + 0.5 x        And        X= -1.1 + 0.2 y
Find correlation coefficient ‘r’.


Question 3:                                                                                    Marks: 5+5=10
  1.  
                    i.            How many different words (even meaningless) can be formed from the word “Component”?
                  ii.            How many distinct four-digit numbers can be performed from the following integers 2, 3,4,5,6 where each integer is used only once?

  1. When a pair of dice is rolled, make the sample space and find the probability
i)                    Total of 5
ii)                  Total of 7?

Solution:

Q3 (ai)
“Component”
n=9 (because the total number of letters are nine)
n1=1(there is one ‘c’)
n2=2(there are two ‘os’)
n3=1(there is one’m’)
n4=1(there is one ‘p’)
n5=2(there are two ‘ns’)
n6=1(there is one ‘e’)
n7= 1(there is one ‘t’)

P = n! / n1! n2! ...................nk!

P= 9! / 1! 2! 1! 1! 2! 1! 1!

P= 9×8×7×6×5×4×3×2×1 / 1×1×2×1×1×1×2×1×1×1
P = 362880 / 4
P = 90720

Q2 (bii)
2, 3,4,5,6

5! / (5-4)! = 5×4×3×2×1 / 1 ! = 120

this is only idea try to solve by your self I m trying to solve other questions.

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