CS610 Assignment No. 3 Solution
Monday, June 06, 2011 Posted In CS and IT Edit ThisCS 610 Computer Networks
Assignment # 03
Spring 2011
Total Marks = 20
Deadline
Your assignment must be uploaded / submitted before or on June 7, 2011
Upload Instructions
Please view the assignment submission process document provided to you by the Virtual University.
Rules for Marking
Please note that your assignment will not be graded if:
• It is submitted after due date
• The file you uploaded does not open
• The file you uploaded is copied from someone else or from internet
• It is in some format other than .doc
Objective
The assignment has been designed to develop the understanding about the concept of Classless and Classful IP addressing.
Note: Material that is an exact copy from handouts or internet would be graded
zero marks. Your solution should consist of the material found through different sources and written in your own words.
Assignment Statements:
Q1: Star organization is using five classless and classful IP addresses in its network. Network engineer wants to compute all the entries which are given in the table. Please fill all entries and mention which methods are used for computing all these entries. (Write only the names of methods). In last row proper steps are required for binary conversion.
[CENTER DIR=LTR]
Address
9.1.4.5/16
145.24.102.1/24
201.16.1.100/24
137.41.102.1/22
193.11.11.100/27
9.1.4.5/16
Methods
Mask
Number of
Network
Bits
Number of
Host Bits
Number of
Subnet Bits
Number of
Hosts Per
Subnet
Class of address
Change address into binary notation
:::::::::::::::::::::::::
Address
9.1.4.5/16, 145.24.102.1/24, 201.16.1.100/24, 137.41.102.1/22, 193.11.11.100/27, 9.1.4.5/16
Methods for each IP
1. Mask
2. Number of
Network
Bits
3. Number of
Host Bits
4. Number of
Subnet Bits
5. Number of
Hosts Per
Subnet
6. Class of address (Calculations Required for each IP)
7. Change address into binary notation (Calculations Required for each IP)
::::::::::::::::::::::::::::::::::
Net work calculator: http://www.subnetmask.info/
http://www.ipaddresslocation.org/cgi-bi ... t-mask.cgi
IP Address: 145.24.102.1/24, Write its mask,no: of network bits,no: of subnet bits,no: of host per subnet?
The /24 tells you that all of the last byte is used for node address and the first 3 bytes for network address. Therefore mask is 255.255.255.0 and its a class C address.
24 its 24bit subnet mask...
255.255.255.0
255 = 8bits
and 8*3 = 24 bits
and last 0 is not counted
Address: 145.24.102.1 10010001.00011000.01100110. 00000001
Netmask: 255.255.255.0 = 24 11111111.11111111.11111111. 00000000
Wildcard: 0.0.0.255 00000000.00000000.00000000. 11111111
=>
Network: 145.24.102.0/24 10010001.00011000.01100110. 00000000
HostMin: 145.24.102.1 10010001.00011000.01100110. 00000001
HostMax: 145.24.102.254 10010001.00011000.01100110. 11111110
Broadcast: 145.24.102.255 10010001.00011000.01100110. 11111111
Hosts/Net: 254 Class B
http://www.ipaddresslocation.org/cgi-bi ... t-mask.cgi
IP Address: 145.24.102.1/24, Write its mask,no: of network bits,no: of subnet bits,no: of host per subnet?
The /24 tells you that all of the last byte is used for node address and the first 3 bytes for network address. Therefore mask is 255.255.255.0 and its a class C address.
24 its 24bit subnet mask...
255.255.255.0
255 = 8bits
and 8*3 = 24 bits
and last 0 is not counted
Address: 145.24.102.1 10010001.00011000.01100110. 00000001
Netmask: 255.255.255.0 = 24 11111111.11111111.11111111. 00000000
Wildcard: 0.0.0.255 00000000.00000000.00000000. 11111111
=>
Network: 145.24.102.0/24 10010001.00011000.01100110. 00000000
HostMin: 145.24.102.1 10010001.00011000.01100110. 00000001
HostMax: 145.24.102.254 10010001.00011000.01100110. 11111110
Broadcast: 145.24.102.255 10010001.00011000.01100110. 11111111
Hosts/Net: 254 Class B
