Mgt613 GDB No. 2 solution
Tuesday, June 07, 2011 Posted In MGT Edit This= 80,000/ (4000-400)
= 80,000/3600
= 22.22
2. For Q = 100 Cameras, the Profit or Loss Will be
P = Q(R-VC)-FC = 100(4000-400)- 80,000 = 100(3600)- 80,000
= 360,000- 80,000 = 280,000/-
3. For P = 50,000
Q = (FC+P)/ ( R-VC)=(80,000+50,000)/(4000-400)
= 130,000/3600 = 36.11
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Solution:
1. How many cameras would be sold in order to break even?
Solution:
QBEP= FC/ ( R-VC)
=Rs. 80,000/ 4000-400= 80,000/3600
= 22.22 cameras = 22 Cameras
2. What would be the profit/loss if the 100 cameras are made and sold in 1 month?
Solution:
For Q =100 cameras, the Profit or Loss would be
P= Q(R-VC)-FC=100(4000-400)-80,000=100X 3600-80,000=360,000-80,000=280,000
3. How many cameras must be sold to realize a profit of Rs. 50,000?
Solution:
For P =50,000
Q = (FC+P)/ ( R-VC)=(80,000+50,000)/(4000-400)
=130,000/3600=36.11 = 36 Cameras